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23111424335603 is a prime number
BaseRepresentation
bin1010100000101000011000…
…01111001101111011110011
310000211102121220021111121102
411100110030033031323303
511012124144112214403
6121053124115515015
74603513432346252
oct520241417157363
9100742556244542
1023111424335603
11740055558428a
1227131952b8a6b
13cb852342cc66
1459c855582799
152a12ab772b88
hex15050c3cdef3

23111424335603 has 2 divisors, whose sum is σ = 23111424335604. Its totient is φ = 23111424335602.

The previous prime is 23111424335543. The next prime is 23111424335617. The reversal of 23111424335603 is 30653342411132.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23111424335603 is a prime.

It is not a weakly prime, because it can be changed into another prime (23111424335303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11555712167801 + 11555712167802.

It is an arithmetic number, because the mean of its divisors is an integer number (11555712167802).

Almost surely, 223111424335603 is an apocalyptic number.

23111424335603 is a deficient number, since it is larger than the sum of its proper divisors (1).

23111424335603 is an equidigital number, since it uses as much as digits as its factorization.

23111424335603 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 155520, while the sum is 38.

Adding to 23111424335603 its reverse (30653342411132), we get a palindrome (53764766746735).

The spelling of 23111424335603 in words is "twenty-three trillion, one hundred eleven billion, four hundred twenty-four million, three hundred thirty-five thousand, six hundred three".