Base | Representation |
---|---|
bin | 100001101000011010110… |
… | …111010011110110000011 |
3 | 22011221110112111121210112 |
4 | 201220122313103312003 |
5 | 300331210114041232 |
6 | 4525420253421535 |
7 | 325655165214536 |
oct | 41503267236603 |
9 | 8157415447715 |
10 | 2311143112067 |
11 | 811172043109 |
12 | 313ab919a8ab |
13 | 139c2ab472ca |
14 | 7dc078b6a1d |
15 | 401b8a994b2 |
hex | 21a1add3d83 |
2311143112067 has 2 divisors, whose sum is σ = 2311143112068. Its totient is φ = 2311143112066.
The previous prime is 2311143112049. The next prime is 2311143112073. The reversal of 2311143112067 is 7602113411132.
2311143112067 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2311143112067 - 232 = 2306848144771 is a prime.
It is not a weakly prime, because it can be changed into another prime (2311143112087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1155571556033 + 1155571556034.
It is an arithmetic number, because the mean of its divisors is an integer number (1155571556034).
Almost surely, 22311143112067 is an apocalyptic number.
2311143112067 is a deficient number, since it is larger than the sum of its proper divisors (1).
2311143112067 is an equidigital number, since it uses as much as digits as its factorization.
2311143112067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 32.
Adding to 2311143112067 its reverse (7602113411132), we get a palindrome (9913256523199).
The spelling of 2311143112067 in words is "two trillion, three hundred eleven billion, one hundred forty-three million, one hundred twelve thousand, sixty-seven".
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