Base | Representation |
---|---|
bin | 100001101000011010110… |
… | …111010011110101110001 |
3 | 22011221110112111121202212 |
4 | 201220122313103311301 |
5 | 300331210114041144 |
6 | 4525420253421505 |
7 | 325655165214512 |
oct | 41503267236561 |
9 | 8157415447685 |
10 | 2311143112049 |
11 | 8111720430a2 |
12 | 313ab919a895 |
13 | 139c2ab472b5 |
14 | 7dc078b6a09 |
15 | 401b8a9949e |
hex | 21a1add3d71 |
2311143112049 has 2 divisors, whose sum is σ = 2311143112050. Its totient is φ = 2311143112048.
The previous prime is 2311143112039. The next prime is 2311143112067. The reversal of 2311143112049 is 9402113411132.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2306167220449 + 4975891600 = 1518607^2 + 70540^2 .
It is a cyclic number.
It is not a de Polignac number, because 2311143112049 - 212 = 2311143107953 is a prime.
It is not a weakly prime, because it can be changed into another prime (2311143112009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1155571556024 + 1155571556025.
It is an arithmetic number, because the mean of its divisors is an integer number (1155571556025).
Almost surely, 22311143112049 is an apocalyptic number.
It is an amenable number.
2311143112049 is a deficient number, since it is larger than the sum of its proper divisors (1).
2311143112049 is an equidigital number, since it uses as much as digits as its factorization.
2311143112049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 32.
The spelling of 2311143112049 in words is "two trillion, three hundred eleven billion, one hundred forty-three million, one hundred twelve thousand, forty-nine".
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