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2311200113 is a prime number
BaseRepresentation
bin1000100111000010…
…0001110101110001
312222001221010112012
42021300201311301
514213131400423
61021201012305
7111162606515
oct21160416561
95861833465
102311200113
11a86680942
12546024095
132aaa97041
1417cd46145
15d7d85078
hex89c21d71

2311200113 has 2 divisors, whose sum is σ = 2311200114. Its totient is φ = 2311200112.

The previous prime is 2311200083. The next prime is 2311200127. The reversal of 2311200113 is 3110021132.

It is an a-pointer prime, because the next prime (2311200127) can be obtained adding 2311200113 to its sum of digits (14).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2310532624 + 667489 = 48068^2 + 817^2 .

It is a cyclic number.

It is not a de Polignac number, because 2311200113 - 210 = 2311199089 is a prime.

It is not a weakly prime, because it can be changed into another prime (2311200173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1155600056 + 1155600057.

It is an arithmetic number, because the mean of its divisors is an integer number (1155600057).

Almost surely, 22311200113 is an apocalyptic number.

It is an amenable number.

2311200113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2311200113 is an equidigital number, since it uses as much as digits as its factorization.

2311200113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 2311200113 is about 48074.9426728727. The cubic root of 2311200113 is about 1322.1452934806.

Adding to 2311200113 its reverse (3110021132), we get a palindrome (5421221245).

The spelling of 2311200113 in words is "two billion, three hundred eleven million, two hundred thousand, one hundred thirteen".