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23112300450073 is a prime number
BaseRepresentation
bin1010100000101010000000…
…11101010101000100011001
310000211111212221211201201111
411100111000131111010121
511012132442403400243
6121053351054020321
74603544231243662
oct520250035250431
9100744787751644
1023112300450073
11740096508202a
12271339a7a76a1
13cb8632ab27a3
1459c8d9a82369
152a130d63239d
hex150540755119

23112300450073 has 2 divisors, whose sum is σ = 23112300450074. Its totient is φ = 23112300450072.

The previous prime is 23112300450011. The next prime is 23112300450103. The reversal of 23112300450073 is 37005400321132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21623588113689 + 1488712336384 = 4650117^2 + 1220128^2 .

It is a cyclic number.

It is not a de Polignac number, because 23112300450073 - 241 = 20913277194521 is a prime.

It is not a weakly prime, because it can be changed into another prime (23112300430073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11556150225036 + 11556150225037.

It is an arithmetic number, because the mean of its divisors is an integer number (11556150225037).

Almost surely, 223112300450073 is an apocalyptic number.

It is an amenable number.

23112300450073 is a deficient number, since it is larger than the sum of its proper divisors (1).

23112300450073 is an equidigital number, since it uses as much as digits as its factorization.

23112300450073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 31.

The spelling of 23112300450073 in words is "twenty-three trillion, one hundred twelve billion, three hundred million, four hundred fifty thousand, seventy-three".