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23112451125301 is a prime number
BaseRepresentation
bin1010100000101010010010…
…11100000111000000110101
310000211112021110100211021111
411100111021130013000311
511012133244442002201
6121053414035315021
74603551041045236
oct520251134070065
9100745243324244
1023112451125301
117400a3213560a
12271342114ba71
13cb8658089b25
1459c911aa508d
152a131b996b51
hex150549707035

23112451125301 has 2 divisors, whose sum is σ = 23112451125302. Its totient is φ = 23112451125300.

The previous prime is 23112451125287. The next prime is 23112451125359. The reversal of 23112451125301 is 10352115421132.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19743794673201 + 3368656452100 = 4443399^2 + 1835390^2 .

It is a cyclic number.

It is not a de Polignac number, because 23112451125301 - 213 = 23112451117109 is a prime.

It is a super-2 number, since 2×231124511253012 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23112451122301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11556225562650 + 11556225562651.

It is an arithmetic number, because the mean of its divisors is an integer number (11556225562651).

Almost surely, 223112451125301 is an apocalyptic number.

It is an amenable number.

23112451125301 is a deficient number, since it is larger than the sum of its proper divisors (1).

23112451125301 is an equidigital number, since it uses as much as digits as its factorization.

23112451125301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7200, while the sum is 31.

Adding to 23112451125301 its reverse (10352115421132), we get a palindrome (33464566546433).

The spelling of 23112451125301 in words is "twenty-three trillion, one hundred twelve billion, four hundred fifty-one million, one hundred twenty-five thousand, three hundred one".