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23112514003 is a prime number
BaseRepresentation
bin10101100001100111…
…001111100111010011
32012122202021100210011
4111201213033213103
5334313300422003
614341233215351
71445515061515
oct254147174723
965582240704
1023112514003
119890458947
124590401557
1322444948b7
141193819bb5
1590413746d
hex5619cf9d3

23112514003 has 2 divisors, whose sum is σ = 23112514004. Its totient is φ = 23112514002.

The previous prime is 23112513997. The next prime is 23112514021. The reversal of 23112514003 is 30041521132.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 23112514003 - 25 = 23112513971 is a prime.

It is not a weakly prime, because it can be changed into another prime (23112514043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11556257001 + 11556257002.

It is an arithmetic number, because the mean of its divisors is an integer number (11556257002).

Almost surely, 223112514003 is an apocalyptic number.

23112514003 is a deficient number, since it is larger than the sum of its proper divisors (1).

23112514003 is an equidigital number, since it uses as much as digits as its factorization.

23112514003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 22.

The spelling of 23112514003 in words is "twenty-three billion, one hundred twelve million, five hundred fourteen thousand, three".