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2311254131 is a prime number
BaseRepresentation
bin1000100111000010…
…1111000001110011
312222002000212121212
42021300233001303
514213140113011
61021202110335
7111163223144
oct21160570163
95862025555
102311254131
11a8670848a
1254604b3ab
132aaab57c4
1417cd5bacb
15d7d9608b
hex89c2f073

2311254131 has 2 divisors, whose sum is σ = 2311254132. Its totient is φ = 2311254130.

The previous prime is 2311254103. The next prime is 2311254139. The reversal of 2311254131 is 1314521132.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2311254131 - 26 = 2311254067 is a prime.

It is a super-2 number, since 2×23112541312 = 10683791316129130322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2311254097 and 2311254106.

It is not a weakly prime, because it can be changed into another prime (2311254139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1155627065 + 1155627066.

It is an arithmetic number, because the mean of its divisors is an integer number (1155627066).

Almost surely, 22311254131 is an apocalyptic number.

2311254131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2311254131 is an equidigital number, since it uses as much as digits as its factorization.

2311254131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 720, while the sum is 23.

The square root of 2311254131 is about 48075.5044799324. The cubic root of 2311254131 is about 1322.1555939139.

Adding to 2311254131 its reverse (1314521132), we get a palindrome (3625775263).

The spelling of 2311254131 in words is "two billion, three hundred eleven million, two hundred fifty-four thousand, one hundred thirty-one".