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231130020222011 = 613789016724951
BaseRepresentation
bin110100100011011000100110…
…110000001001010000111011
31010022100210222111201212112202
4310203120212300021100323
5220243313240134101021
62135323355423500415
766453410236302521
oct6443304660112073
91108323874655482
10231130020222011
1167710766960529
1221b0a66815770b
139bc760cacb971
144110a77468311
151bac3500d9a0b
hexd23626c0943b

231130020222011 has 4 divisors (see below), whose sum is σ = 234919036947024. Its totient is φ = 227341003497000.

The previous prime is 231130020221963. The next prime is 231130020222083. The reversal of 231130020222011 is 110222020031132.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 231130020222011 - 214 = 231130020205627 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (231130020222611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1894508362415 + ... + 1894508362536.

It is an arithmetic number, because the mean of its divisors is an integer number (58729759236756).

Almost surely, 2231130020222011 is an apocalyptic number.

231130020222011 is a deficient number, since it is larger than the sum of its proper divisors (3789016725013).

231130020222011 is an equidigital number, since it uses as much as digits as its factorization.

231130020222011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3789016725012.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 231130020222011 its reverse (110222020031132), we get a palindrome (341352040253143).

The spelling of 231130020222011 in words is "two hundred thirty-one trillion, one hundred thirty billion, twenty million, two hundred twenty-two thousand, eleven".

Divisors: 1 61 3789016724951 231130020222011