Base | Representation |
---|---|
bin | 100001101000100100001… |
… | …110111100110111010101 |
3 | 22011221212111021211001121 |
4 | 201220210032330313111 |
5 | 300332020334214331 |
6 | 4525444030523541 |
7 | 325662114301210 |
oct | 41504416746725 |
9 | 8157774254047 |
10 | 2311300304341 |
11 | 811242847a86 |
12 | 313b419665b1 |
13 | 139c54593aa2 |
14 | 7dc20714777 |
15 | 401c7799c11 |
hex | 21a243bcdd5 |
2311300304341 has 16 divisors (see below), whose sum is σ = 2855660613760. Its totient is φ = 1826119805760.
The previous prime is 2311300304309. The next prime is 2311300304359. The reversal of 2311300304341 is 1434030031132.
2311300304341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 2311300304341 - 25 = 2311300304309 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2311300304371) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 234835590 + ... + 234845431.
It is an arithmetic number, because the mean of its divisors is an integer number (178478788360).
Almost surely, 22311300304341 is an apocalyptic number.
It is an amenable number.
2311300304341 is a deficient number, since it is larger than the sum of its proper divisors (544360309419).
2311300304341 is a wasteful number, since it uses less digits than its factorization.
2311300304341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 469681084.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 2311300304341 its reverse (1434030031132), we get a palindrome (3745330335473).
The spelling of 2311300304341 in words is "two trillion, three hundred eleven billion, three hundred million, three hundred four thousand, three hundred forty-one".
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