Base | Representation |
---|---|
bin | 10101100001101001… |
… | …001001000000101001 |
3 | 2012122210012121212101 |
4 | 111201221021000221 |
5 | 334313412324431 |
6 | 14341252013401 |
7 | 1445522232265 |
oct | 254151110051 |
9 | 65583177771 |
10 | 23113011241 |
11 | 9890768491 |
12 | 4590601261 |
13 | 224460a018 |
14 | 11939090a5 |
15 | 9041d4961 |
hex | 561a49029 |
23113011241 has 2 divisors, whose sum is σ = 23113011242. Its totient is φ = 23113011240.
The previous prime is 23113011193. The next prime is 23113011247. The reversal of 23113011241 is 14211031132.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20626991641 + 2486019600 = 143621^2 + 49860^2 .
It is a cyclic number.
It is not a de Polignac number, because 23113011241 - 233 = 14523076649 is a prime.
It is a super-2 number, since 2×231130112412 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (23113011247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11556505620 + 11556505621.
It is an arithmetic number, because the mean of its divisors is an integer number (11556505621).
Almost surely, 223113011241 is an apocalyptic number.
It is an amenable number.
23113011241 is a deficient number, since it is larger than the sum of its proper divisors (1).
23113011241 is an equidigital number, since it uses as much as digits as its factorization.
23113011241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 23113011241 its reverse (14211031132), we get a palindrome (37324042373).
The spelling of 23113011241 in words is "twenty-three billion, one hundred thirteen million, eleven thousand, two hundred forty-one".
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