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231132201323 = 631736588919
BaseRepresentation
bin1101011101000010001…
…1011000000101101011
3211002121000000101002212
43113100203120011223
512241324320420243
6254103005115335
722461446203232
oct3272043300553
9732530011085
10231132201323
118a028113901
1238965858b4b
1318a4612ab8a
14b288a4bb19
15602b695318
hex35d08d816b

231132201323 has 4 divisors (see below), whose sum is σ = 231168796560. Its totient is φ = 231095606088.

The previous prime is 231132201271. The next prime is 231132201329. The reversal of 231132201323 is 323102231132.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 231132201323 - 26 = 231132201259 is a prime.

It is a super-4 number, since 4×2311322013234 (a number of 47 digits) contains 4444 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (231132201329) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18288143 + ... + 18300776.

It is an arithmetic number, because the mean of its divisors is an integer number (57792199140).

Almost surely, 2231132201323 is an apocalyptic number.

231132201323 is a deficient number, since it is larger than the sum of its proper divisors (36595237).

231132201323 is an equidigital number, since it uses as much as digits as its factorization.

231132201323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36595236.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 231132201323 its reverse (323102231132), we get a palindrome (554234432455).

The spelling of 231132201323 in words is "two hundred thirty-one billion, one hundred thirty-two million, two hundred one thousand, three hundred twenty-three".

Divisors: 1 6317 36588919 231132201323