Base | Representation |
---|---|
bin | 110100100011011011011110… |
… | …100000011001110100001111 |
3 | 1010022101002221100201110120021 |
4 | 310203123132200121310033 |
5 | 220243341043343300442 |
6 | 2135325025352403011 |
7 | 66453546522331462 |
oct | 6443333640316417 |
9 | 1108332840643507 |
10 | 231133103103247 |
11 | 67711aa908a864 |
12 | 21b0b1886a6467 |
13 | 9bc79b1711b47 |
14 | 4110c8aa872d9 |
15 | 1bac480aa0e67 |
hex | d236de819d0f |
231133103103247 has 2 divisors, whose sum is σ = 231133103103248. Its totient is φ = 231133103103246.
The previous prime is 231133103103229. The next prime is 231133103103299. The reversal of 231133103103247 is 742301301331132.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-231133103103247 is a prime.
It is a super-3 number, since 3×2311331031032473 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (231133103103047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115566551551623 + 115566551551624.
It is an arithmetic number, because the mean of its divisors is an integer number (115566551551624).
Almost surely, 2231133103103247 is an apocalyptic number.
231133103103247 is a deficient number, since it is larger than the sum of its proper divisors (1).
231133103103247 is an equidigital number, since it uses as much as digits as its factorization.
231133103103247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27216, while the sum is 34.
Adding to 231133103103247 its reverse (742301301331132), we get a palindrome (973434404434379).
The spelling of 231133103103247 in words is "two hundred thirty-one trillion, one hundred thirty-three billion, one hundred three million, one hundred three thousand, two hundred forty-seven".
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