Base | Representation |
---|---|
bin | 1010100000101101001100… |
… | …10111101000011010110101 |
3 | 10000211200022010002200021121 |
4 | 11100112212113220122311 |
5 | 11012144443104420001 |
6 | 121054232452343541 |
7 | 4603634502201256 |
oct | 520264627503265 |
9 | 100750263080247 |
10 | 23114010232501 |
11 | 7401662216961 |
12 | 2713797314bb1 |
13 | cb88460a5876 |
14 | 59ca1cb92b2d |
15 | 2a13ad7b96a1 |
hex | 1505a65e86b5 |
23114010232501 has 2 divisors, whose sum is σ = 23114010232502. Its totient is φ = 23114010232500.
The previous prime is 23114010232483. The next prime is 23114010232571. The reversal of 23114010232501 is 10523201041132.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 16943505830001 + 6170504402500 = 4116249^2 + 2484050^2 .
It is a cyclic number.
It is not a de Polignac number, because 23114010232501 - 233 = 23105420297909 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23114010232571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11557005116250 + 11557005116251.
It is an arithmetic number, because the mean of its divisors is an integer number (11557005116251).
Almost surely, 223114010232501 is an apocalyptic number.
It is an amenable number.
23114010232501 is a deficient number, since it is larger than the sum of its proper divisors (1).
23114010232501 is an equidigital number, since it uses as much as digits as its factorization.
23114010232501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 23114010232501 its reverse (10523201041132), we get a palindrome (33637211273633).
The spelling of 23114010232501 in words is "twenty-three trillion, one hundred fourteen billion, ten million, two hundred thirty-two thousand, five hundred one".
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