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231140352181 is a prime number
BaseRepresentation
bin1101011101000100001…
…0011110000010110101
3211002121120100110222111
43113101002132002311
512241333412232211
6254103455531021
722461605401534
oct3272102360265
9732546313874
10231140352181
118a031780752
1238968529a71
1318a47a22b7b
14b289b7031b
15602c255421
hex35d109e0b5

231140352181 has 2 divisors, whose sum is σ = 231140352182. Its totient is φ = 231140352180.

The previous prime is 231140352143. The next prime is 231140352193. The reversal of 231140352181 is 181253041132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 220774057956 + 10366294225 = 469866^2 + 101815^2 .

It is a cyclic number.

It is not a de Polignac number, because 231140352181 - 227 = 231006134453 is a prime.

It is a super-4 number, since 4×2311403521814 (a number of 47 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (231140382181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115570176090 + 115570176091.

It is an arithmetic number, because the mean of its divisors is an integer number (115570176091).

Almost surely, 2231140352181 is an apocalyptic number.

It is an amenable number.

231140352181 is a deficient number, since it is larger than the sum of its proper divisors (1).

231140352181 is an equidigital number, since it uses as much as digits as its factorization.

231140352181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 31.

The spelling of 231140352181 in words is "two hundred thirty-one billion, one hundred forty million, three hundred fifty-two thousand, one hundred eighty-one".