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231143421235 = 5335913762633
BaseRepresentation
bin1101011101000100111…
…0001011010100110011
3211002121210010101221011
43113101032023110303
512241340203434420
6254104045411351
722461643443316
oct3272116132463
9732553111834
10231143421235
118a033487561
1238969569b57
1318a48558a8c
14b28a32c97d
15602c65e95a
hex35d138b533

231143421235 has 8 divisors (see below), whose sum is σ = 277454701440. Its totient is φ = 184859673024.

The previous prime is 231143421233. The next prime is 231143421259. The reversal of 231143421235 is 532124341132.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 231143421235 - 21 = 231143421233 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 231143421197 and 231143421206.

It is not an unprimeable number, because it can be changed into a prime (231143421233) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6864522 + ... + 6898111.

It is an arithmetic number, because the mean of its divisors is an integer number (34681837680).

Almost surely, 2231143421235 is an apocalyptic number.

231143421235 is a deficient number, since it is larger than the sum of its proper divisors (46311280205).

231143421235 is a wasteful number, since it uses less digits than its factorization.

231143421235 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13765997.

The product of its digits is 17280, while the sum is 31.

Adding to 231143421235 its reverse (532124341132), we get a palindrome (763267762367).

The spelling of 231143421235 in words is "two hundred thirty-one billion, one hundred forty-three million, four hundred twenty-one thousand, two hundred thirty-five".

Divisors: 1 5 3359 16795 13762633 68813165 46228684247 231143421235