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23114414433 = 3115483127747
BaseRepresentation
bin10101100001101110…
…011111100101100001
32012122212211220200110
4111201232133211201
5334314242230213
614341342041533
71445540165235
oct254156374541
965585756613
1023114414433
119891536750
124590b792a9
1322449ab906
141193b925c5
159043b05c3
hex561b9f961

23114414433 has 16 divisors (see below), whose sum is σ = 33627361536. Its totient is φ = 14006071440.

The previous prime is 23114414377. The next prime is 23114414467. The reversal of 23114414433 is 33441441132.

It is not a de Polignac number, because 23114414433 - 221 = 23112317281 is a prime.

It is a super-2 number, since 2×231144144332 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 23114414433.

It is not an unprimeable number, because it can be changed into a prime (23114418433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 117066 + ... + 244812.

It is an arithmetic number, because the mean of its divisors is an integer number (2101710096).

Almost surely, 223114414433 is an apocalyptic number.

It is an amenable number.

23114414433 is a deficient number, since it is larger than the sum of its proper divisors (10512947103).

23114414433 is a wasteful number, since it uses less digits than its factorization.

23114414433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 133244.

The product of its digits is 13824, while the sum is 30.

Adding to 23114414433 its reverse (33441441132), we get a palindrome (56555855565).

The spelling of 23114414433 in words is "twenty-three billion, one hundred fourteen million, four hundred fourteen thousand, four hundred thirty-three".

Divisors: 1 3 11 33 5483 16449 60313 127747 180939 383241 1405217 4215651 700436801 2101310403 7704804811 23114414433