Base | Representation |
---|---|
bin | 1010100000101101111101… |
… | …10111110001101110101111 |
3 | 10000211201100202121200221012 |
4 | 11100112332313301232233 |
5 | 11012201313323444211 |
6 | 121054341335255435 |
7 | 4603650623261111 |
oct | 520267667615657 |
9 | 100751322550835 |
10 | 23114421312431 |
11 | 740185326a339 |
12 | 2713890b1a57b |
13 | cb88b02c6427 |
14 | 59ca5b5dd3b1 |
15 | 2a13d491ad8b |
hex | 1505bedf1baf |
23114421312431 has 4 divisors (see below), whose sum is σ = 23114832167592. Its totient is φ = 23114010457272.
The previous prime is 23114421312403. The next prime is 23114421312457. The reversal of 23114421312431 is 13421312441132.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23114421312431 - 234 = 23097241443247 is a prime.
It is a super-2 number, since 2×231144213124312 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23114421312131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 205343180 + ... + 205455713.
It is an arithmetic number, because the mean of its divisors is an integer number (5778708041898).
Almost surely, 223114421312431 is an apocalyptic number.
23114421312431 is a deficient number, since it is larger than the sum of its proper divisors (410855161).
23114421312431 is an equidigital number, since it uses as much as digits as its factorization.
23114421312431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 410855160.
The product of its digits is 13824, while the sum is 32.
Adding to 23114421312431 its reverse (13421312441132), we get a palindrome (36535733753563).
The spelling of 23114421312431 in words is "twenty-three trillion, one hundred fourteen billion, four hundred twenty-one million, three hundred twelve thousand, four hundred thirty-one".
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