Base | Representation |
---|---|
bin | 1010100000101110000000… |
… | …01011000010101111010010 |
3 | 10000211201102021200122210112 |
4 | 11100113000023002233102 |
5 | 11012201334420440200 |
6 | 121054343435201322 |
7 | 4603651306641353 |
oct | 520270013025722 |
9 | 100751367618715 |
10 | 23114443140050 |
11 | 7401864618799 |
12 | 27138982a6242 |
13 | cb88b4999692 |
14 | 59ca60481d2a |
15 | 2a13d67cd535 |
hex | 1505c02c2bd2 |
23114443140050 has 48 divisors (see below), whose sum is σ = 46816186161600. Its totient is φ = 8457117480000.
The previous prime is 23114443140037. The next prime is 23114443140059. The reversal of 23114443140050 is 5004134441132.
It is a junction number, because it is equal to n+sod(n) for n = 23114443139989 and 23114443140016.
It is not an unprimeable number, because it can be changed into a prime (23114443140059) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 419472326 + ... + 419527425.
It is an arithmetic number, because the mean of its divisors is an integer number (975337211700).
Almost surely, 223114443140050 is an apocalyptic number.
23114443140050 is an abundant number, since it is smaller than the sum of its proper divisors (23701743021550).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
23114443140050 is a wasteful number, since it uses less digits than its factorization.
23114443140050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 838999811 (or 838999806 counting only the distinct ones).
The product of its (nonzero) digits is 23040, while the sum is 32.
Adding to 23114443140050 its reverse (5004134441132), we get a palindrome (28118577581182).
The spelling of 23114443140050 in words is "twenty-three trillion, one hundred fourteen billion, four hundred forty-three million, one hundred forty thousand, fifty".
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