Base | Representation |
---|---|
bin | 10101100001110001… |
… | …111010101110100011 |
3 | 2012122221112111221222 |
4 | 111201301322232203 |
5 | 334320004441120 |
6 | 14341413205255 |
7 | 1445550624164 |
oct | 254161725643 |
9 | 65587474858 |
10 | 23115312035 |
11 | 9891a9a072 |
12 | 459133082b |
13 | 2244c3433a |
14 | 1193d4776b |
15 | 9044db525 |
hex | 561c7aba3 |
23115312035 has 4 divisors (see below), whose sum is σ = 27738374448. Its totient is φ = 18492249624.
The previous prime is 23115312007. The next prime is 23115312061. The reversal of 23115312035 is 53021351132.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23115312035 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 23115311995 and 23115312013.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2311531199 + ... + 2311531208.
It is an arithmetic number, because the mean of its divisors is an integer number (6934593612).
Almost surely, 223115312035 is an apocalyptic number.
23115312035 is a deficient number, since it is larger than the sum of its proper divisors (4623062413).
23115312035 is an equidigital number, since it uses as much as digits as its factorization.
23115312035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4623062412.
The product of its (nonzero) digits is 2700, while the sum is 26.
Adding to 23115312035 its reverse (53021351132), we get a palindrome (76136663167).
The spelling of 23115312035 in words is "twenty-three billion, one hundred fifteen million, three hundred twelve thousand, thirty-five".
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