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23115651131 = 53994281469
BaseRepresentation
bin10101100001110011…
…001101100000111011
32012122222011202010002
4111201303031200323
5334320101314011
614341424343215
71445553535616
oct254163154073
965588152102
1023115651131
119892200911
124591474b0b
1322450227a1
141193dd517d
15904556c3b
hex561ccd83b

23115651131 has 4 divisors (see below), whose sum is σ = 23119938000. Its totient is φ = 23111364264.

The previous prime is 23115651103. The next prime is 23115651253. The reversal of 23115651131 is 13115651132.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 23115651131 - 218 = 23115388987 is a prime.

It is a super-2 number, since 2×231156511312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23115651094 and 23115651103.

It is not an unprimeable number, because it can be changed into a prime (23115651631) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2135336 + ... + 2146133.

It is an arithmetic number, because the mean of its divisors is an integer number (5779984500).

Almost surely, 223115651131 is an apocalyptic number.

23115651131 is a deficient number, since it is larger than the sum of its proper divisors (4286869).

23115651131 is an equidigital number, since it uses as much as digits as its factorization.

23115651131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4286868.

The product of its digits is 2700, while the sum is 29.

Subtracting from 23115651131 its reverse (13115651132), we obtain a palindrome (9999999999).

The spelling of 23115651131 in words is "twenty-three billion, one hundred fifteen million, six hundred fifty-one thousand, one hundred thirty-one".

Divisors: 1 5399 4281469 23115651131