Base | Representation |
---|---|
bin | 1010100000110001100010… |
… | …10011010011001101000010 |
3 | 10000211220022120002112121110 |
4 | 11100120301103103031002 |
5 | 11012214231312130200 |
6 | 121055300035504150 |
7 | 4604046324410040 |
oct | 520306123231502 |
9 | 100756276075543 |
10 | 23116341130050 |
11 | 7402648a20773 |
12 | 2714127a58056 |
13 | cb8b27c7839c |
14 | 59cba0585390 |
15 | 2a1498240b50 |
hex | 1506314d3342 |
23116341130050 has 96 divisors (see below), whose sum is σ = 67631809572864. Its totient is φ = 5113292040000.
The previous prime is 23116341130009. The next prime is 23116341130067. The reversal of 23116341130050 is 5003114361132.
It is a super-2 number, since 2×231163411300502 (a number of 28 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 355057176 + ... + 355122275.
It is an arithmetic number, because the mean of its divisors is an integer number (704498016384).
Almost surely, 223116341130050 is an apocalyptic number.
23116341130050 is an abundant number, since it is smaller than the sum of its proper divisors (44515468442814).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
23116341130050 is a wasteful number, since it uses less digits than its factorization.
23116341130050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 710179504 (or 710179499 counting only the distinct ones).
The product of its (nonzero) digits is 6480, while the sum is 30.
Adding to 23116341130050 its reverse (5003114361132), we get a palindrome (28119455491182).
The spelling of 23116341130050 in words is "twenty-three trillion, one hundred sixteen billion, three hundred forty-one million, one hundred thirty thousand, fifty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •