Base | Representation |
---|---|
bin | 110100100100011001110010… |
… | …000011010000011011110101 |
3 | 1010022121111121201200100100001 |
4 | 310210121302003100123311 |
5 | 220300440101232000203 |
6 | 2135415452021351301 |
7 | 66461435414143423 |
oct | 6444316203203365 |
9 | 1108544551610301 |
10 | 231200003000053 |
11 | 6773840935a47a |
12 | 21b20139268531 |
13 | 9c010b37c64b9 |
14 | 41141d5a7a113 |
15 | 1bae098e4791d |
hex | d246720d06f5 |
231200003000053 has 2 divisors, whose sum is σ = 231200003000054. Its totient is φ = 231200003000052.
The previous prime is 231200002999981. The next prime is 231200003000059. The reversal of 231200003000053 is 350000300002132.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 139325515926129 + 91874487073924 = 11803623^2 + 9585118^2 .
It is a cyclic number.
It is not a de Polignac number, because 231200003000053 - 213 = 231200002991861 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (231200003000059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115600001500026 + 115600001500027.
It is an arithmetic number, because the mean of its divisors is an integer number (115600001500027).
Almost surely, 2231200003000053 is an apocalyptic number.
It is an amenable number.
231200003000053 is a deficient number, since it is larger than the sum of its proper divisors (1).
231200003000053 is an equidigital number, since it uses as much as digits as its factorization.
231200003000053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 19.
Adding to 231200003000053 its reverse (350000300002132), we get a palindrome (581200303002185).
The spelling of 231200003000053 in words is "two hundred thirty-one trillion, two hundred billion, three million, fifty-three", and thus it is an aban number.
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