Base | Representation |
---|---|
bin | 1010100000111000111111… |
… | …10110110000111001101101 |
3 | 10000212021122111002010112012 |
4 | 11100130133312300321231 |
5 | 11012300430402413031 |
6 | 121101201130251005 |
7 | 4604250443234444 |
oct | 520343766607155 |
9 | 100767574063465 |
10 | 23120343404141 |
11 | 7404312118505 |
12 | 2714a64286a65 |
13 | cb93151b4bc9 |
14 | 59d05dd2bd5b |
15 | 2a162e7b4b2b |
hex | 15071fdb0e6d |
23120343404141 has 4 divisors (see below), whose sum is σ = 23120890582812. Its totient is φ = 23119796225472.
The previous prime is 23120343404117. The next prime is 23120343404143. The reversal of 23120343404141 is 14140434302132.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 11903397016900 + 11216946387241 = 3450130^2 + 3349171^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23120343404141 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 23120343404098 and 23120343404107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23120343404143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 273525950 + ... + 273610463.
It is an arithmetic number, because the mean of its divisors is an integer number (5780222645703).
Almost surely, 223120343404141 is an apocalyptic number.
It is an amenable number.
23120343404141 is a deficient number, since it is larger than the sum of its proper divisors (547178671).
23120343404141 is an equidigital number, since it uses as much as digits as its factorization.
23120343404141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 547178670.
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 23120343404141 its reverse (14140434302132), we get a palindrome (37260777706273).
It can be divided in two parts, 2312034 and 3404141, that added together give a palindrome (5716175).
The spelling of 23120343404141 in words is "twenty-three trillion, one hundred twenty billion, three hundred forty-three million, four hundred four thousand, one hundred forty-one".
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