Base | Representation |
---|---|
bin | 1010100000111001011000… |
… | …11000000001111110001111 |
3 | 10000212022012010022122012120 |
4 | 11100130230120001332033 |
5 | 11012301343140421112 |
6 | 121101234032304023 |
7 | 4604255603506236 |
oct | 520345430017617 |
9 | 100768163278176 |
10 | 23120553451407 |
11 | 740440a743095 |
12 | 2714b026a2013 |
13 | cb9349879429 |
14 | 59d07dba7b1d |
15 | 2a1642e55e8c |
hex | 15072c601f8f |
23120553451407 has 32 divisors (see below), whose sum is σ = 33038040645120. Its totient is φ = 14344669468800.
The previous prime is 23120553451393. The next prime is 23120553451459. The reversal of 23120553451407 is 70415435502132.
It is not a de Polignac number, because 23120553451407 - 219 = 23120552927119 is a prime.
It is a super-4 number, since 4×231205534514074 (a number of 55 digits) contains 4444 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23120553451007) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 111337269 + ... + 111544737.
It is an arithmetic number, because the mean of its divisors is an integer number (1032438770160).
Almost surely, 223120553451407 is an apocalyptic number.
23120553451407 is a deficient number, since it is larger than the sum of its proper divisors (9917487193713).
23120553451407 is a wasteful number, since it uses less digits than its factorization.
23120553451407 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 251183.
The product of its (nonzero) digits is 504000, while the sum is 42.
Adding to 23120553451407 its reverse (70415435502132), we get a palindrome (93535988953539).
The spelling of 23120553451407 in words is "twenty-three trillion, one hundred twenty billion, five hundred fifty-three million, four hundred fifty-one thousand, four hundred seven".
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