Base | Representation |
---|---|
bin | 10101100010001000… |
… | …111011001101110111 |
3 | 2012200100212221101001 |
4 | 111202020323031313 |
5 | 334323030441401 |
6 | 14342150344131 |
7 | 1445653114201 |
oct | 254210731567 |
9 | 65610787331 |
10 | 23121343351 |
11 | 9895439527 |
12 | 459335b047 |
13 | 2246266672 |
14 | 1194a77771 |
15 | 904ccd601 |
hex | 56223b377 |
23121343351 has 4 divisors (see below), whose sum is σ = 23144034600. Its totient is φ = 23098652104.
The previous prime is 23121343309. The next prime is 23121343361. The reversal of 23121343351 is 15334312132.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23121343351 - 211 = 23121341303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23121343361) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11344096 + ... + 11346133.
It is an arithmetic number, because the mean of its divisors is an integer number (5786008650).
Almost surely, 223121343351 is an apocalyptic number.
23121343351 is a deficient number, since it is larger than the sum of its proper divisors (22691249).
23121343351 is a wasteful number, since it uses less digits than its factorization.
23121343351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22691248.
The product of its digits is 6480, while the sum is 28.
Adding to 23121343351 its reverse (15334312132), we get a palindrome (38455655483).
The spelling of 23121343351 in words is "twenty-three billion, one hundred twenty-one million, three hundred forty-three thousand, three hundred fifty-one".
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