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23121343351 = 101922690229
BaseRepresentation
bin10101100010001000…
…111011001101110111
32012200100212221101001
4111202020323031313
5334323030441401
614342150344131
71445653114201
oct254210731567
965610787331
1023121343351
119895439527
12459335b047
132246266672
141194a77771
15904ccd601
hex56223b377

23121343351 has 4 divisors (see below), whose sum is σ = 23144034600. Its totient is φ = 23098652104.

The previous prime is 23121343309. The next prime is 23121343361. The reversal of 23121343351 is 15334312132.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 23121343351 - 211 = 23121341303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (23121343361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11344096 + ... + 11346133.

It is an arithmetic number, because the mean of its divisors is an integer number (5786008650).

Almost surely, 223121343351 is an apocalyptic number.

23121343351 is a deficient number, since it is larger than the sum of its proper divisors (22691249).

23121343351 is a wasteful number, since it uses less digits than its factorization.

23121343351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22691248.

The product of its digits is 6480, while the sum is 28.

Adding to 23121343351 its reverse (15334312132), we get a palindrome (38455655483).

The spelling of 23121343351 in words is "twenty-three billion, one hundred twenty-one million, three hundred forty-three thousand, three hundred fifty-one".

Divisors: 1 1019 22690229 23121343351