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2312331200113 = 11210211927283
BaseRepresentation
bin100001101001100001101…
…011100000011001110001
322012001112100002202012111
4201221201223200121301
5300341123241400423
64530134214325321
7326026502621224
oct41514153403161
98161470082174
102312331200113
11811721753260
1231418b059841
1313a08a02a89c
147dcbb5c55bb
154023803060d
hex21a61ae0671

2312331200113 has 4 divisors (see below), whose sum is σ = 2522543127408. Its totient is φ = 2102119272820.

The previous prime is 2312331200093. The next prime is 2312331200143. The reversal of 2312331200113 is 3110021332132.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2312331200113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2312331200143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105105963631 + ... + 105105963652.

It is an arithmetic number, because the mean of its divisors is an integer number (630635781852).

Almost surely, 22312331200113 is an apocalyptic number.

It is an amenable number.

2312331200113 is a deficient number, since it is larger than the sum of its proper divisors (210211927295).

2312331200113 is a wasteful number, since it uses less digits than its factorization.

2312331200113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 210211927294.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 2312331200113 its reverse (3110021332132), we get a palindrome (5422352532245).

The spelling of 2312331200113 in words is "two trillion, three hundred twelve billion, three hundred thirty-one million, two hundred thousand, one hundred thirteen".

Divisors: 1 11 210211927283 2312331200113