2312401124433 has 4 divisors (see below), whose sum is σ = 3083201499248. Its totient is φ = 1541600749620.

The previous prime is 2312401124417. The next prime is 2312401124437. The reversal of 2312401124433 is 3344211042132.

2312401124433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2312401124433 - 2⁴ = 2312401124417 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 2312401124433.

It is not an unprimeable number, because it can be changed into a prime (2312401124437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 385400187403 + ... + 385400187408.

It is an arithmetic number, because the mean of its divisors is an integer number (770800374812).

Almost surely, 2^{2312401124433} is an apocalyptic number.

It is an amenable number.

2312401124433 is a deficient number, since it is larger than the sum of its proper divisors (770800374815).

2312401124433 is an equidigital number, since it uses as much as digits as its factorization.

2312401124433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 770800374814.

The product of its (nonzero) digits is 13824, while the sum is 30.

Adding to 2312401124433 its reverse (3344211042132), we get a palindrome (5656612166565).

The spelling of 2312401124433 in words is "two trillion, three hundred twelve billion, four hundred one million, one hundred twenty-four thousand, four hundred thirty-three".