231241443133 has 4 divisors (see below), whose sum is σ = 231403947328. Its totient is φ = 231078938940.

The previous prime is 231241443119. The next prime is 231241443151. The reversal of 231241443133 is 331344142132.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 231241443133 - 2²⁵ = 231207888701 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 231241443095 and 231241443104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (231241443233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81249963 + ... + 81252808.

It is an arithmetic number, because the mean of its divisors is an integer number (57850986832).

Almost surely, 2^231241443133 is an apocalyptic number.

It is an amenable number.

231241443133 is a deficient number, since it is larger than the sum of its proper divisors (162504195).

231241443133 is a wasteful number, since it uses less digits than its factorization.

231241443133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 162504194.

The product of its digits is 20736, while the sum is 31.

Adding to 231241443133 its reverse (331344142132), we get a palindrome (562585585265).

The spelling of 231241443133 in words is "two hundred thirty-one billion, two hundred forty-one million, four hundred forty-three thousand, one hundred thirty-three".