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23124311413 = 73303473059
BaseRepresentation
bin10101100010010100…
…001111110101110101
32012200120110201210021
4111202110033311311
5334324310431123
614342334125141
71446020255350
oct254224176565
965616421707
1023124311413
119897086475
1245943507b1
132246a65608
14119520b297
159051b7c5d
hex56250fd75

23124311413 has 4 divisors (see below), whose sum is σ = 26427784480. Its totient is φ = 19820838348.

The previous prime is 23124311407. The next prime is 23124311443. The reversal of 23124311413 is 31411342132.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 23124311413 - 25 = 23124311381 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (23124311443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1651736523 + ... + 1651736536.

It is an arithmetic number, because the mean of its divisors is an integer number (6606946120).

Almost surely, 223124311413 is an apocalyptic number.

It is an amenable number.

23124311413 is a deficient number, since it is larger than the sum of its proper divisors (3303473067).

23124311413 is an equidigital number, since it uses as much as digits as its factorization.

23124311413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3303473066.

The product of its digits is 1728, while the sum is 25.

Adding to 23124311413 its reverse (31411342132), we get a palindrome (54535653545).

The spelling of 23124311413 in words is "twenty-three billion, one hundred twenty-four million, three hundred eleven thousand, four hundred thirteen".

Divisors: 1 7 3303473059 23124311413