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231243314101 = 1207119156931
BaseRepresentation
bin1101011101011100101…
…1001111001110110101
3211002212202002111011221
43113113023033032311
512242041242022401
6254122014430341
722464265511212
oct3272713171665
9732782074157
10231243314101
118a084905548
1238996b023b1
1318a63162897
14b2996d2b09
1560362e27a1
hex35d72cf3b5

231243314101 has 4 divisors (see below), whose sum is σ = 231262483104. Its totient is φ = 231224145100.

The previous prime is 231243314053. The next prime is 231243314123. The reversal of 231243314101 is 101413342132.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-231243314101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (231243314131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9566395 + ... + 9590536.

It is an arithmetic number, because the mean of its divisors is an integer number (57815620776).

Almost surely, 2231243314101 is an apocalyptic number.

It is an amenable number.

231243314101 is a deficient number, since it is larger than the sum of its proper divisors (19169003).

231243314101 is a wasteful number, since it uses less digits than its factorization.

231243314101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19169002.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 231243314101 its reverse (101413342132), we get a palindrome (332656656233).

The spelling of 231243314101 in words is "two hundred thirty-one billion, two hundred forty-three million, three hundred fourteen thousand, one hundred one".

Divisors: 1 12071 19156931 231243314101