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2312511401413 is a prime number
BaseRepresentation
bin100001101001101100011…
…010111010110111000101
322012001222220011220220201
4201221230122322313011
5300342010404321123
64530204132530501
7326034121405363
oct41515432726705
98161886156821
102312511401413
11811804443154
1231421b480a31
1313a0b8472285
147dcd74d2633
1540248c785ad
hex21a6c6badc5

2312511401413 has 2 divisors, whose sum is σ = 2312511401414. Its totient is φ = 2312511401412.

The previous prime is 2312511401407. The next prime is 2312511401423. The reversal of 2312511401413 is 3141041152132.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1175127545089 + 1137383856324 = 1084033^2 + 1066482^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2312511401413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2312511401423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1156255700706 + 1156255700707.

It is an arithmetic number, because the mean of its divisors is an integer number (1156255700707).

Almost surely, 22312511401413 is an apocalyptic number.

It is an amenable number.

2312511401413 is a deficient number, since it is larger than the sum of its proper divisors (1).

2312511401413 is an equidigital number, since it uses as much as digits as its factorization.

2312511401413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 2312511401413 its reverse (3141041152132), we get a palindrome (5453552553545).

The spelling of 2312511401413 in words is "two trillion, three hundred twelve billion, five hundred eleven million, four hundred one thousand, four hundred thirteen".