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231300100103 = 1092122019267
BaseRepresentation
bin1101011101101010001…
…1110111000000000111
3211010000200221111221012
43113122203313000013
512242200311200403
6254131403512435
722465555261112
oct3273243670007
9733020844835
10231300100103
118a103970726
12389b1b2871b
1318a71b55977
14b2a3075579
15603b2aced8
hex35da8f7007

231300100103 has 4 divisors (see below), whose sum is σ = 233422119480. Its totient is φ = 229178080728.

The previous prime is 231300100091. The next prime is 231300100127. The reversal of 231300100103 is 301001003132.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 231300100103 - 26 = 231300100039 is a prime.

It is a super-2 number, since 2×2313001001032 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (231300100903) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1061009525 + ... + 1061009742.

It is an arithmetic number, because the mean of its divisors is an integer number (58355529870).

Almost surely, 2231300100103 is an apocalyptic number.

231300100103 is a deficient number, since it is larger than the sum of its proper divisors (2122019377).

231300100103 is a wasteful number, since it uses less digits than its factorization.

231300100103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2122019376.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 231300100103 its reverse (301001003132), we get a palindrome (532301103235).

The spelling of 231300100103 in words is "two hundred thirty-one billion, three hundred million, one hundred thousand, one hundred three".

Divisors: 1 109 2122019267 231300100103