23130244111333 has 2 divisors, whose sum is σ = 23130244111334. Its totient is φ = 23130244111332.

The previous prime is 23130244111321. The next prime is 23130244111363. The reversal of 23130244111333 is 33311144203132.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 21155749813444 + 1974494297889 = 4599538^2 + 1405167^2 .

It is a cyclic number.

It is not a de Polignac number, because 23130244111333 - 2⁵ = 23130244111301 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 23130244111295 and 23130244111304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23130244111313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11565122055666 + 11565122055667.

It is an arithmetic number, because the mean of its divisors is an integer number (11565122055667).

Almost surely, 2^{23130244111333} is an apocalyptic number.

It is an amenable number.

23130244111333 is a deficient number, since it is larger than the sum of its proper divisors (1).

23130244111333 is an equidigital number, since it uses as much as digits as its factorization.

23130244111333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 23130244111333 its reverse (33311144203132), we get a palindrome (56441388314465).

The spelling of 23130244111333 in words is "twenty-three trillion, one hundred thirty billion, two hundred forty-four million, one hundred eleven thousand, three hundred thirty-three".