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2313111310003 = 13447713974261
BaseRepresentation
bin100001101010010000001…
…011011000111010110011
322012010112201000102210101
4201222100023120322303
5300344222443410003
64530343443013231
7326055024504124
oct41522013307263
98163481012711
102313111310003
11811a9203937a
1231436836a217
1313a182838380
147dd5305404b
154028177911d
hex21a902d8eb3

2313111310003 has 8 divisors (see below), whose sum is σ = 2491099215696. Its totient is φ = 2135131442400.

The previous prime is 2313111309931. The next prime is 2313111310021. The reversal of 2313111310003 is 3000131113132.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2313111310003 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2313111310073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1405108 + ... + 2569153.

It is an arithmetic number, because the mean of its divisors is an integer number (311387401962).

Almost surely, 22313111310003 is an apocalyptic number.

2313111310003 is a deficient number, since it is larger than the sum of its proper divisors (177987905693).

2313111310003 is a wasteful number, since it uses less digits than its factorization.

2313111310003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4019045.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 2313111310003 its reverse (3000131113132), we get a palindrome (5313242423135).

The spelling of 2313111310003 in words is "two trillion, three hundred thirteen billion, one hundred eleven million, three hundred ten thousand, three".

Divisors: 1 13 44771 582023 3974261 51665393 177931639231 2313111310003