Base | Representation |
---|---|
bin | 1010100001001101000100… |
… | …10000000001111001010111 |
3 | 10000220022110121000201200001 |
4 | 11100212202100001321113 |
5 | 11012440013434000043 |
6 | 121110142411432131 |
7 | 4605111512262001 |
oct | 520464220017127 |
9 | 100808417021601 |
10 | 23131121000023 |
11 | 7408942860843 |
12 | 2716b71755647 |
13 | cba34200c78a |
14 | 59d7a3467371 |
15 | 2a1a60a7174d |
hex | 1509a2401e57 |
23131121000023 has 2 divisors, whose sum is σ = 23131121000024. Its totient is φ = 23131121000022.
The previous prime is 23131121000011. The next prime is 23131121000077. The reversal of 23131121000023 is 32000012113132.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23131121000023 - 25 = 23131120999991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23131121000003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11565560500011 + 11565560500012.
It is an arithmetic number, because the mean of its divisors is an integer number (11565560500012).
Almost surely, 223131121000023 is an apocalyptic number.
23131121000023 is a deficient number, since it is larger than the sum of its proper divisors (1).
23131121000023 is an equidigital number, since it uses as much as digits as its factorization.
23131121000023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 23131121000023 its reverse (32000012113132), we get a palindrome (55131133113155).
The spelling of 23131121000023 in words is "twenty-three trillion, one hundred thirty-one billion, one hundred twenty-one million, twenty-three", and thus it is an aban number.
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