Base | Representation |
---|---|
bin | 1101011101101101010… |
… | …1111000000000010011 |
3 | 211010001121121122021012 |
4 | 3113123111320000103 |
5 | 12242212140231121 |
6 | 254132552521135 |
7 | 22466104566362 |
oct | 3273325700023 |
9 | 733047548235 |
10 | 231313211411 |
11 | 8a110306417 |
12 | 389b63b01ab |
13 | 18a74796739 |
14 | b2a4ac97d9 |
15 | 603c4ecc5b |
hex | 35db578013 |
231313211411 has 2 divisors, whose sum is σ = 231313211412. Its totient is φ = 231313211410.
The previous prime is 231313211401. The next prime is 231313211461. The reversal of 231313211411 is 114112313132.
231313211411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 231313211411 - 226 = 231246102547 is a prime.
It is a super-2 number, since 2×2313132114112 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (231313211401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115656605705 + 115656605706.
It is an arithmetic number, because the mean of its divisors is an integer number (115656605706).
Almost surely, 2231313211411 is an apocalyptic number.
231313211411 is a deficient number, since it is larger than the sum of its proper divisors (1).
231313211411 is an equidigital number, since it uses as much as digits as its factorization.
231313211411 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 432, while the sum is 23.
Adding to 231313211411 its reverse (114112313132), we get a palindrome (345425524543).
The spelling of 231313211411 in words is "two hundred thirty-one billion, three hundred thirteen million, two hundred eleven thousand, four hundred eleven".
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