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231321121117 is a prime number
BaseRepresentation
bin1101011101101111010…
…0000011000101011101
3211010002011111111100021
43113123310003011131
512242221201333432
6254133434232141
722466232041632
oct3273364030535
9733064444307
10231321121117
118a114819069
12389b8b85651
1318a76305a38
14b2a5b88189
15603d061697
hex35dbd0315d

231321121117 has 2 divisors, whose sum is σ = 231321121118. Its totient is φ = 231321121116.

The previous prime is 231321121099. The next prime is 231321121121. The reversal of 231321121117 is 711121123132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 224461803076 + 6859318041 = 473774^2 + 82821^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-231321121117 is a prime.

It is a super-2 number, since 2×2313211211172 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 231321121091 and 231321121100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (231321121217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115660560558 + 115660560559.

It is an arithmetic number, because the mean of its divisors is an integer number (115660560559).

Almost surely, 2231321121117 is an apocalyptic number.

It is an amenable number.

231321121117 is a deficient number, since it is larger than the sum of its proper divisors (1).

231321121117 is an equidigital number, since it uses as much as digits as its factorization.

231321121117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 504, while the sum is 25.

Adding to 231321121117 its reverse (711121123132), we get a palindrome (942442244249).

The spelling of 231321121117 in words is "two hundred thirty-one billion, three hundred twenty-one million, one hundred twenty-one thousand, one hundred seventeen".