Base | Representation |
---|---|
bin | 1101011101101111010… |
… | …0110001001110101111 |
3 | 211010002011212002121122 |
4 | 3113123310301032233 |
5 | 12242221223411002 |
6 | 254133442251155 |
7 | 22466233456655 |
oct | 3273364611657 |
9 | 733064762548 |
10 | 231321310127 |
11 | 8a114938076 |
12 | 389b9056abb |
13 | 18a76370a8b |
14 | b2a5bd6dd5 |
15 | 603d09c6a2 |
hex | 35dbd313af |
231321310127 has 2 divisors, whose sum is σ = 231321310128. Its totient is φ = 231321310126.
The previous prime is 231321310109. The next prime is 231321310139. The reversal of 231321310127 is 721013123132.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 231321310127 - 212 = 231321306031 is a prime.
It is a super-2 number, since 2×2313213101272 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 231321310096 and 231321310105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (231321310177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115660655063 + 115660655064.
It is an arithmetic number, because the mean of its divisors is an integer number (115660655064).
Almost surely, 2231321310127 is an apocalyptic number.
231321310127 is a deficient number, since it is larger than the sum of its proper divisors (1).
231321310127 is an equidigital number, since it uses as much as digits as its factorization.
231321310127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 26.
Adding to 231321310127 its reverse (721013123132), we get a palindrome (952334433259).
The spelling of 231321310127 in words is "two hundred thirty-one billion, three hundred twenty-one million, three hundred ten thousand, one hundred twenty-seven".
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