Base | Representation |
---|---|
bin | 110100100110001011100000… |
… | …110111010011100001010111 |
3 | 1010100001011211100122210101202 |
4 | 310212023200313103201113 |
5 | 220304440201013102411 |
6 | 2135551525422543115 |
7 | 66503320543665614 |
oct | 6446134067234127 |
9 | 1110034740583352 |
10 | 231322121222231 |
11 | 67785184969236 |
12 | 21b3b93a437a9b |
13 | 9c0c7757ab870 |
14 | 411a09c45350b |
15 | 1bb2344d6483b |
hex | d262e0dd3857 |
231322121222231 has 16 divisors (see below), whose sum is σ = 249706751616000. Its totient is φ = 213022155370080.
The previous prime is 231322121222197. The next prime is 231322121222261. The reversal of 231322121222231 is 132222121223132.
231322121222231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 231322121222231 - 210 = 231322121221207 is a prime.
It is a super-2 number, since 2×2313221212222312 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 231322121222194 and 231322121222203.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (231322121222261) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13100546 + ... + 25184688.
It is an arithmetic number, because the mean of its divisors is an integer number (15606671976000).
Almost surely, 2231322121222231 is an apocalyptic number.
231322121222231 is a deficient number, since it is larger than the sum of its proper divisors (18384630393769).
231322121222231 is a wasteful number, since it uses less digits than its factorization.
231322121222231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12087646.
The product of its digits is 6912, while the sum is 29.
Adding to 231322121222231 its reverse (132222121223132), we get a palindrome (363544242445363).
Subtracting from 231322121222231 its reverse (132222121223132), we obtain a palindrome (99099999999099).
The spelling of 231322121222231 in words is "two hundred thirty-one trillion, three hundred twenty-two billion, one hundred twenty-one million, two hundred twenty-two thousand, two hundred thirty-one".
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