Base | Representation |
---|---|
bin | 1101011101101111111… |
… | …1011101110001011101 |
3 | 211010002101010112211021 |
4 | 3113123333131301131 |
5 | 12242222433122023 |
6 | 254134022324141 |
7 | 22466266345366 |
oct | 3273377356135 |
9 | 733071115737 |
10 | 231324114013 |
11 | 8a116482733 |
12 | 389b9b89651 |
13 | 18a76b13095 |
14 | b2a6326b6d |
15 | 603d45335d |
hex | 35dbfddc5d |
231324114013 has 4 divisors (see below), whose sum is σ = 231384626368. Its totient is φ = 231263601660.
The previous prime is 231324113947. The next prime is 231324114017. The reversal of 231324114013 is 310411423132.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 231324114013 - 225 = 231290559581 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (231324114017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30250443 + ... + 30258088.
It is an arithmetic number, because the mean of its divisors is an integer number (57846156592).
Almost surely, 2231324114013 is an apocalyptic number.
It is an amenable number.
231324114013 is a deficient number, since it is larger than the sum of its proper divisors (60512355).
231324114013 is an equidigital number, since it uses as much as digits as its factorization.
231324114013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 60512354.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 231324114013 its reverse (310411423132), we get a palindrome (541735537145).
The spelling of 231324114013 in words is "two hundred thirty-one billion, three hundred twenty-four million, one hundred fourteen thousand, thirteen".
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