Base | Representation |
---|---|
bin | 100001101010011011100… |
… | …000101001001101011110 |
3 | 22012011000221202120221202 |
4 | 201222123200221031132 |
5 | 300400120131244014 |
6 | 4530414353555502 |
7 | 326062523505131 |
oct | 41523340511536 |
9 | 8164027676852 |
10 | 2313301431134 |
11 | 81207a394181 |
12 | 3143bbb75b92 |
13 | 13a1b3043c95 |
14 | 7dd703c4218 |
15 | 402932d13de |
hex | 21a9b82935e |
2313301431134 has 4 divisors (see below), whose sum is σ = 3469952146704. Its totient is φ = 1156650715566.
The previous prime is 2313301431131. The next prime is 2313301431167. The reversal of 2313301431134 is 4311341033132.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×23133014311342 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2313301431097 and 2313301431106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2313301431131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 578325357782 + ... + 578325357785.
It is an arithmetic number, because the mean of its divisors is an integer number (867488036676).
Almost surely, 22313301431134 is an apocalyptic number.
2313301431134 is a deficient number, since it is larger than the sum of its proper divisors (1156650715570).
2313301431134 is a wasteful number, since it uses less digits than its factorization.
2313301431134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1156650715569.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 2313301431134 its reverse (4311341033132), we get a palindrome (6624642464266).
The spelling of 2313301431134 in words is "two trillion, three hundred thirteen billion, three hundred one million, four hundred thirty-one thousand, one hundred thirty-four".
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