Base | Representation |
---|---|
bin | 110100100110010100110011… |
… | …110001011100100101100101 |
3 | 1010100002010120221111102221020 |
4 | 310212110303301130211211 |
5 | 220310121121121130041 |
6 | 2140000300044241353 |
7 | 66504123100212264 |
oct | 6446246361344545 |
9 | 1110063527442836 |
10 | 231332102130021 |
11 | 67789436922a62 |
12 | 21b41864b40259 |
13 | 9c106a6542b69 |
14 | 411a767c465db |
15 | 1bb272b200866 |
hex | d26533c5c965 |
231332102130021 has 4 divisors (see below), whose sum is σ = 308442802840032. Its totient is φ = 154221401420012.
The previous prime is 231332102129963. The next prime is 231332102130047. The reversal of 231332102130021 is 120031201233132.
231332102130021 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 231332102130021 - 213 = 231332102121829 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 231332102129973 and 231332102130000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (231332102130071) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38555350355001 + ... + 38555350355006.
It is an arithmetic number, because the mean of its divisors is an integer number (77110700710008).
Almost surely, 2231332102130021 is an apocalyptic number.
It is an amenable number.
231332102130021 is a deficient number, since it is larger than the sum of its proper divisors (77110700710011).
231332102130021 is an equidigital number, since it uses as much as digits as its factorization.
231332102130021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 77110700710010.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 231332102130021 its reverse (120031201233132), we get a palindrome (351363303363153).
The spelling of 231332102130021 in words is "two hundred thirty-one trillion, three hundred thirty-two billion, one hundred two million, one hundred thirty thousand, twenty-one".
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