Base | Representation |
---|---|
bin | 10101100010110111… |
… | …000010110100011101 |
3 | 2012201012122011102011 |
4 | 111202313002310131 |
5 | 334334124324432 |
6 | 14343301431221 |
7 | 1446160636264 |
oct | 254267026435 |
9 | 65635564364 |
10 | 23133433117 |
11 | 98a1246773 |
12 | 459740b511 |
13 | 224890a482 |
14 | 11965035db |
15 | 905dba847 |
hex | 562dc2d1d |
23133433117 has 2 divisors, whose sum is σ = 23133433118. Its totient is φ = 23133433116.
The previous prime is 23133433091. The next prime is 23133433121. The reversal of 23133433117 is 71133433132.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 21033410841 + 2100022276 = 145029^2 + 45826^2 .
It is a cyclic number.
It is not a de Polignac number, because 23133433117 - 27 = 23133432989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23133433177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11566716558 + 11566716559.
It is an arithmetic number, because the mean of its divisors is an integer number (11566716559).
Almost surely, 223133433117 is an apocalyptic number.
It is an amenable number.
23133433117 is a deficient number, since it is larger than the sum of its proper divisors (1).
23133433117 is an equidigital number, since it uses as much as digits as its factorization.
23133433117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 13608, while the sum is 31.
Adding to 23133433117 its reverse (71133433132), we get a palindrome (94266866249).
The spelling of 23133433117 in words is "twenty-three billion, one hundred thirty-three million, four hundred thirty-three thousand, one hundred seventeen".
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