Base | Representation |
---|---|
bin | 1010100001010011010000… |
… | …10001101000101111011001 |
3 | 10000220122001010112120020020 |
4 | 11100221220101220233121 |
5 | 11013013314441410131 |
6 | 121111452212221053 |
7 | 4605260033404020 |
oct | 520515021505731 |
9 | 100818033476206 |
10 | 23134443310041 |
11 | 740a2981534a8 |
12 | 271773a30a789 |
13 | cba7514037ab |
14 | 59d9da7ad8b7 |
15 | 2a1ba757e996 |
hex | 150a68468bd9 |
23134443310041 has 64 divisors (see below), whose sum is σ = 37468584211968. Its totient is φ = 12394628333568.
The previous prime is 23134443310001. The next prime is 23134443310067. The reversal of 23134443310041 is 14001334443132.
It is not a de Polignac number, because 23134443310041 - 26 = 23134443309977 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23134443309984 and 23134443310011.
It is not an unprimeable number, because it can be changed into a prime (23134443310001) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 182856781 + ... + 182983253.
It is an arithmetic number, because the mean of its divisors is an integer number (585446628312).
Almost surely, 223134443310041 is an apocalyptic number.
23134443310041 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
It is an amenable number.
23134443310041 is a deficient number, since it is larger than the sum of its proper divisors (14334140901927).
23134443310041 is a wasteful number, since it uses less digits than its factorization.
23134443310041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 128450.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 23134443310041 its reverse (14001334443132), we get a palindrome (37135777753173).
The spelling of 23134443310041 in words is "twenty-three trillion, one hundred thirty-four billion, four hundred forty-three million, three hundred ten thousand, forty-one".
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