Base | Representation |
---|---|
bin | 1101011110000010000… |
… | …1011100111011101101 |
3 | 211010021200011200100121 |
4 | 3113200201130323231 |
5 | 12242401413213313 |
6 | 254145335524541 |
7 | 22501211446216 |
oct | 3274041347355 |
9 | 733250150317 |
10 | 231400132333 |
11 | 8a155384397 |
12 | 38a1b529751 |
13 | 18a897ab036 |
14 | b2b247440d |
15 | 6044e6c28d |
hex | 35e085ceed |
231400132333 has 2 divisors, whose sum is σ = 231400132334. Its totient is φ = 231400132332.
The previous prime is 231400132309. The next prime is 231400132351. The reversal of 231400132333 is 333231004132.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 168380556964 + 63019575369 = 410342^2 + 251037^2 .
It is a cyclic number.
It is not a de Polignac number, because 231400132333 - 233 = 222810197741 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 231400132298 and 231400132307.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (231400132433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115700066166 + 115700066167.
It is an arithmetic number, because the mean of its divisors is an integer number (115700066167).
Almost surely, 2231400132333 is an apocalyptic number.
It is an amenable number.
231400132333 is a deficient number, since it is larger than the sum of its proper divisors (1).
231400132333 is an equidigital number, since it uses as much as digits as its factorization.
231400132333 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 231400132333 its reverse (333231004132), we get a palindrome (564631136465).
The spelling of 231400132333 in words is "two hundred thirty-one billion, four hundred million, one hundred thirty-two thousand, three hundred thirty-three".
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