231404011303133 has 2 divisors, whose sum is σ = 231404011303134. Its totient is φ = 231404011303132.

The previous prime is 231404011303099. The next prime is 231404011303313. The reversal of 231404011303133 is 331303110404132.

Together with next prime (231404011303313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 215726386891129 + 15677624412004 = 14687627^2 + 3959498^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-231404011303133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 231404011303096 and 231404011303105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (231404011305133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115702005651566 + 115702005651567.

It is an arithmetic number, because the mean of its divisors is an integer number (115702005651567).

Almost surely, 2^{231404011303133} is an apocalyptic number.

It is an amenable number.

231404011303133 is a deficient number, since it is larger than the sum of its proper divisors (1).

231404011303133 is an equidigital number, since it uses as much as digits as its factorization.

231404011303133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 231404011303133 its reverse (331303110404132), we get a palindrome (562707121707265).

The spelling of 231404011303133 in words is "two hundred thirty-one trillion, four hundred four billion, eleven million, three hundred three thousand, one hundred thirty-three".