2314140253433 has 2 divisors, whose sum is σ = 2314140253434. Its totient is φ = 2314140253432.

The previous prime is 2314140253429. The next prime is 2314140253457. The reversal of 2314140253433 is 3343520414132.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1469070050704 + 845070202729 = 1212052^2 + 919277^2 .

It is a cyclic number.

It is not a de Polignac number, because 2314140253433 - 2² = 2314140253429 is a prime.

It is a super-2 number, since 2×2314140253433² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2314140253393 and 2314140253402.

It is not a weakly prime, because it can be changed into another prime (2314140253423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1157070126716 + 1157070126717.

It is an arithmetic number, because the mean of its divisors is an integer number (1157070126717).

Almost surely, 2^{2314140253433} is an apocalyptic number.

It is an amenable number.

2314140253433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2314140253433 is an equidigital number, since it uses as much as digits as its factorization.

2314140253433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 35.

Adding to 2314140253433 its reverse (3343520414132), we get a palindrome (5657660667565).

The spelling of 2314140253433 in words is "two trillion, three hundred fourteen billion, one hundred forty million, two hundred fifty-three thousand, four hundred thirty-three".