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23143054047 = 37714351349
BaseRepresentation
bin10101100011011011…
…101111101011011111
32012201212201221211220
4111203123233223133
5334344110212142
614344243544423
71446335466531
oct254333575337
965655657756
1023143054047
1198a6718053
12459a68b113
13224a8c8629
1411978c9851
15906b6b2ec
hex5636efadf

23143054047 has 4 divisors (see below), whose sum is σ = 30857405400. Its totient is φ = 15428702696.

The previous prime is 23143054019. The next prime is 23143054097. The reversal of 23143054047 is 74045034132.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 23143054047 - 210 = 23143053023 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 23143053999 and 23143054017.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (23143054007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3857175672 + ... + 3857175677.

It is an arithmetic number, because the mean of its divisors is an integer number (7714351350).

Almost surely, 223143054047 is an apocalyptic number.

23143054047 is a deficient number, since it is larger than the sum of its proper divisors (7714351353).

23143054047 is an equidigital number, since it uses as much as digits as its factorization.

23143054047 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7714351352.

The product of its (nonzero) digits is 40320, while the sum is 33.

Adding to 23143054047 its reverse (74045034132), we get a palindrome (97188088179).

The spelling of 23143054047 in words is "twenty-three billion, one hundred forty-three million, fifty-four thousand, forty-seven".

Divisors: 1 3 7714351349 23143054047