Base | Representation |
---|---|
bin | 1010100001100101000101… |
… | …00111101011110111010111 |
3 | 10000221112201222220121200011 |
4 | 11100302202213223313113 |
5 | 11013142414044300002 |
6 | 121120113512501051 |
7 | 4606046123660656 |
oct | 520624247536727 |
9 | 100845658817604 |
10 | 23144012103127 |
11 | 7413358518363 |
12 | 271956a9aa787 |
13 | cbb617974236 |
14 | 5a026756719d |
15 | 2a20676628d7 |
hex | 150ca29ebdd7 |
23144012103127 has 2 divisors, whose sum is σ = 23144012103128. Its totient is φ = 23144012103126.
The previous prime is 23144012103109. The next prime is 23144012103131. The reversal of 23144012103127 is 72130121044132.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 23144012103127 - 211 = 23144012101079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23144012103167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11572006051563 + 11572006051564.
It is an arithmetic number, because the mean of its divisors is an integer number (11572006051564).
Almost surely, 223144012103127 is an apocalyptic number.
23144012103127 is a deficient number, since it is larger than the sum of its proper divisors (1).
23144012103127 is an equidigital number, since it uses as much as digits as its factorization.
23144012103127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 23144012103127 its reverse (72130121044132), we get a palindrome (95274133147259).
The spelling of 23144012103127 in words is "twenty-three trillion, one hundred forty-four billion, twelve million, one hundred three thousand, one hundred twenty-seven".
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